Assume:

ri!n = 5

1. Generate the rows

enumerate(ri!n) + 1

enumerate(5) gives:

{0, 1, 2, 3, 4}

Adding 1 gives:

{1, 2, 3, 4, 5}

So the outer a!forEach() runs 5 times.

2. Get the current row number

Inside the outer loop:

fv!item

represents the current number.

So the iterations are:

fv!item = 1

fv!item = 2

fv!item = 3

fv!item = 4

fv!item = 5

3. Generate numbers for the current row

local!numbers: enumerate(fv!item) + 1

For example, when:

fv!item = 3

we get:

enumerate(3)

→ {0,1,2}

+ 1

→ {1,2,3}

So:

local!numbers = {1,2,3}

4. Convert the numbers into a string

joinarray(

local!numbers,

" "

)

For:

{1,2,3}

the result is:

"1 2 3"

5. Calculate the row sum

sum(local!numbers)

For:

{1,2,3}

the result is:

6

6. Combine everything

joinarray(local!numbers, " ")

& " | Sum: "

& sum(local!numbers)

becomes:

"1 2 3 | Sum: 6"

Complete execution for n = 5

Final output

{

"1 | Sum: 1",

"1 2 | Sum: 3",

"1 2 3 | Sum: 6",

"1 2 3 4 | Sum: 10",

"1 2 3 4 5 | Sum: 15"

}

Core idea: The outer loop creates each row, local!numbers creates the sequence for that row, joinarray() formats it, and sum() calculates the row total.